can please remind me how can create ascending integer number given numbers of digits?
example:
y(3) -> 123 y(5) -> 12345 y(8) -> 12345678 thank you
for values in range 1 10, how about:
def y(size): return 1234567890 / (10**(10-size)) size in range(1,11): print y(size) gives:
1 12 123 1234 12345 123456 1234567 12345678 123456789 1234567890 as alternative way of thinking it, try:
def y(size): return int("1234567890"[:size])
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