Python - create an ascending integer number -


can please remind me how can create ascending integer number given numbers of digits?

example:

y(3) -> 123 y(5) -> 12345 y(8) -> 12345678 

thank you

for values in range 1 10, how about:

def y(size):     return 1234567890 / (10**(10-size))  size in range(1,11):     print y(size) 

gives:

1 12 123 1234 12345 123456 1234567 12345678 123456789 1234567890 

as alternative way of thinking it, try:

def y(size):     return int("1234567890"[:size]) 

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