python - How do I extract JavaScript code and parse only the HTML -

i'm learning how programme , want scrape webpage minus javascript code. i'm following example book. code below should return html code website, returns title of site , javascript code @ bottom. can please let me know went wrong? cheers.

import urllib2  bs4 import beautifulsoup  url = "http://www.theurl.com/" page = urllib2.urlopen(url) soup = beautifulsoup(page, "html.parser")  [x.extract() x in soup.find_all('script')]  print soup.get_text() 

this returns after title.

var _gaq = _gaq || [];       _gaq.push(['_setaccount', 'ua-11092338-1']);       _gaq.push(['_trackpageview']);       (function() {         var ga = document.createelement('script'); ga.type = 'text/javascript'; ga.async = true;         ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') + '.google-analytics.com/ga.js';         var s = document.getelementsbytagname('script')[0]; s.parentnode.insertbefore(ga, s);       })(); 

have tried printing soup.contents? because when print soup.get_text(), shall print relatively text. try following code please.

import urllib2  bs4 import beautifulsoup  url = "http://www.theurl.com/" page = urllib2.urlopen(url) soup = beautifulsoup(page, "html.parser")  [x.extract() x in soup.find_all('script')]  html =soup.contents in html:     print