c - Showing the scores and number of times each score was obtained -

my name adriel, new site , programming. anyways need , guidance assignment. create program in c allow user enter 5000 exam scores. give user 5 options average grade, show exams high low, curve exams 5 or down 5 and 1 can't display scores , how many times obtained.

this code:

main() {      //declared variables     char choice;     int i, j, a, n;     int examscore = 0, high = 0, low = 0, avg = 0, count = 0, sum = 0, scorecount = 0;     int highlow[5000], highexam, lowexam;      do{//begin while #1         cls;         flush;         printf("=========================\n");         printf("===== score program =====\n");         printf("=========================\n");         printf("a. exam scores\n");         printf("b. exams average\n");         printf("c. exam score high - low\n");         printf("d. times scores obtained\n");         printf("e. curved 5 pts\n");         printf("f. curved down 5 pts\n");         printf("q. exit program\n");         printf("=========================\n");         printf("enter choice: ");         scanf(" %c", &choice);         choice = toupper(choice);         switch (choice){//begin switch         case 'a':             cls;             printf("please enter number of exams:\n");             scanf("%d", &n);              printf("please enter %d numbers\n", n);             (i = 0; < n; i++){                 scanf("%d", &highlow[i]);             }//end loop             highlow[examscore];             count++;             sum = sum + examscore;             avg = sum / count;             highexam = examscore + 5;             lowexam = examscore - 5;             cls;             (i = 0; < n; i++)             {                 (j = + 1; j<n; ++j)                 {                     if (highlow[i]<highlow[j])                     {                         = highlow[i];                         highlow[i] = highlow[j];                         highlow[j] = a;                     }                 }             }               pause;             break;          case 'b':             cls;             printf("exam average is: %i\n", avg);             pause;             break;          case 'c':             cls;             printf("the numbers arranged in descending order given below\n");              (i = 0; < n; ++i)              {                  printf("%i\n", highlow[i]);             }             pause;             break;          case 'd':             cls;             printf("amount of times scored obtained: %i-%i\n", examscore, count);             pause;             break;          case 'e':             cls;         //  printf("exam scores curved 5 pts: %i\n", highexam);             pause;             break;          case 'f':             cls;         //  printf("exam scores curved down 5 pts: %i\n", lowexam);             pause;             break;          case 'q':             cls;             printf("quitting program. goodbye.\n");             pause;             break;          default:             printf("- invalid entry -\n");             pause;             break;          }//end switch      } while (choice != 'q');//end while #1   }//end main 

as may see still far done, other parts not big concern me. , advice appreciate.

why difficult count number of times each score in highlow array?

i thinking of different approach until noticed had sorted array of scores, duplicate scores adjacent each other. should easy enough @ value of highlow[0] , compare highlow[1] see if highlow[0] duplicated. until find next isn't duplicate, start looking duplicates of next number.