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- php parse/syntax errors; , how solve them? 11 answers
im creating option if, because if need on load item b selected current view. dont need js. trying this, error because of if, done right think here is:
echo ('<option value="?m=ticketsmith&ticket_company=' . $row['company_id'] . '&type='.$type.'"'. if ($show_uid == $row['company_id']) { echo ' selected="selected"';}'/>' . $row['company_id'].', ' . $row["company_name"]) ; i hope guys me. , here error messege: parse error: syntax error, unexpected 'if' (t_if) in
echo ('<option value="?m=ticketsmith&ticket_company=' . $row['company_id'] . '&type='.$type.'"'. ($show_uid == $row['company_id'] ? ' selected="selected"' : '' ) . '/>' . $row['company_id'].', ' . $row["company_name"]) ; the change this
if ($show_uid == $row['company_id']) { echo ' selected="selected"';} to this
($show_uid == $row['company_id'] ? ' selected="selected"' : '' )
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