java - Split string against some characters except the # character -

i want split string against following characters

~!@$%^&*()_+­=<>,.?/:;"'{}|[]\, \n,\t, space

i tried use \\s regex delimiter don't want # included split character string this #funny should result this is #funny resulting values.

i have tried following doesn't work.

this #funny".split("\\s")

but doesn't work. ideas?

just specify characters want in square bracket, means any of. single escape java characters (like \") , double escape regex special characters (like \\[):

@test public void testname() throws exception {     string[] split = "this #funny".split("[~!@$%^&*()_+­=<>,.?/:;\"'{}|\\[\\]\\\\ \\n\\t]");     (string string : split)      {         logger.debug(string);     } }