parsing - Scala - Parse String until end of string -

with scala-parser-combinators, want try parse postfix string(end). previous parser cought end contents. how fix it? (just changing "[^z]".r not answer.)

val input = "aaabbbzzz" parseall(body, input) // java.lang.illegalstateexception: `zzz' expected end of source found  def body: parser[list[string]] = content.+ <~ end def content: parser[string] = repchar // more complex (repchar | foo | bar) def repchar: parser[string] = ".{3}".r // if change "[^z]{3}", no flexibility. def end: parser[string] = "zzz" 

i want try followings.

"""(.*)(?=zzz)""".r.into(str => ...check content.+ or not... <~ end) 

1. search strings until end string.
2. then parse them parser.

another way fix use not combinator. need check parsing not end value.

the trick not doesn't consume input, if not(end) succeeds (meaning end failed) didn't reach stopping condition can parse 3 characters content parser made end parser failing.

as non-greedy approach linked in comments, fail input has characters after "zzz" in input (such "aaabbbzzzzzz" example).

but may sufficient use case. give try with:

def body: parser[list[string]] = rep(not(end) ~> content) <~ end 

in fact kind of takeuntil parser, because parses content repeatedly until you're able parse end.