i've been searching god knows how long, couldn't piece of code work:
solution n = 3/2*((n-n`mod`3)+3) it compiles when call it, throws 2 errors, first 1 being
no instance (integral a0) arising use of `solution' here i'm trying achieve
solution 9 = 3/2* ((n-n`mod`3)+3) = 3/2 * ((9-0)+3) = 3/2 * (12) = 18
haskell won't let add fractional (3/2) integral
((n - n `mod` 3) + 3) without explicitly telling want adding fromintegral latter.
solution n = 3/2 * fromintegral ((n-n`mod`3)+3) should work.
there's quite overview of numeric types in real world haskell. never remember details though, , add in fromintegral whenever it's required.
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