awk - Compare two files according to first column and print whole line -

i ask question example. have 2 files:

file1-

tr100013|c0_g1 tr100013|c0_g2 tr10009|c0_g1 tr10009|c0_g2 

file2-

tr100013|c0_g1  at1g01360.1 78.79   165 35  0   301 795 19  183 2e-089  272 tr100013|c0_g2  at1g01360.1 78.79   165 35  0   301 795 19  183 2e-089  272 tr10009|c0_g1   at1g16240.3 77.42   62  14  0   261 76  113 174 4e-025  95.9 tr10009|c0_g2   at1g16240.2 69.17   120 37  0   1007    648 113 232 2e-050  171 tr29295|c0_g1   at1g22540.1 69.19   172 53  2   6   521 34  200 2e-053  180 tr49005|c5_g1   at5g24530.1 69.21   302 90  1   909 13  39  340 5e-157  446 

expected output :

tr100013|c0_g1  at1g01360.1 78.79   165 35  0   301 795 19  183 2e-089  272 tr100013|c0_g2  at1g01360.1 78.79   165 35  0   301 795 19  183 2e-089  272 tr10009|c0_g1   at1g16240.3 77.42   62  14  0   261 76  113 174 4e-025  95.9 tr10009|c0_g2   at1g16240.2 69.17   120 37  0   1007    648 113 232 2e-050  171 

i want compare 2 files. if first column same in both files, print whole line of second file common in both files.

using awk:

 awk 'nr==fnr{a[$1]++;next};a[$1]' file1 file2 

grep can same:

grep -wf file1 file2 

-w match whole word only.
-f specifies file pattern.