windows - How to get process location using Python 2.7? -

i searching way retrieve location path (path of corresponding exe-file) of windows process using python. managed lots of information pid, name etc. no chance location.

any suggestions may me appreciated.

have checked out psutil?

pip install psutil 

or better...

conda install psutil 

it has exe method may trick

exe()[source] process executable absolute path. on systems may empty string. return value cached after first call.

>>> import psutil >>> psutil.pids() [1, 2, 3, 4, 5, 6, 7, 46, 48, 50, 51, 178, 182, 222, 223, 224,  268, 1215, 1216, 1220, 1221, 1243, 1244, 1301, 1601, 2237, 2355,  2637, 2774, 3932, 4176, 4177, 4185, 4187, 4189, 4225, 4243, 4245,  4263, 4282, 4306, 4311, 4312, 4313, 4314, 4337, 4339, 4357, 4358,  4363, 4383, 4395, 4408, 4433, 4443, 4445, 4446, 5167, 5234, 5235,  5252, 5318, 5424, 5644, 6987, 7054, 7055, 7071] >>> >>> p = psutil.process(7055) >>> p.name() 'python' >>> p.exe() '/usr/bin/python'