python - How does HttpResponse(status=<code>) work in django? -

i'm experimenting http error codes in django have question httpresponse(status=<code>). example, want send http error code 405, have following code:

def myview(request):    if request.method == 'post':       ...    else:       return httpresponse(status=405) 

also have template http error code (405.html) , put following code line in urls.py

handler405 = 'handling_error.views.bad_method' 

and bad_method view following:

def bad_method(request):     datos_template = {}     return render(request, '405.html', datos_template, status=405) 

i thought in way django redirect correct template according http error code, doesn't work, then:

have done incorrect something? how httpresponse(status=) work in django? goal of sending http error code through httpresponse(status=)?

sorry, many questions :p

i hope can me.

httpresponse(status=[code]) way of sending actual http status code in header of response. arrives @ client status_code, not changing of data except http header. can pass status code properly-working response, , still show before, if go browser's console see read "405" page.

http headers transferred each request , response web server parsing , providing metadata/info developers. 404 pages have content sent them, tell user there 404; if didn't, user blank page , have no idea went wrong.

if want signify error, can take @ these docs. alternatively, can use httpresponseredirect (see here) option direct error-view serves custom error response.