this sample email data in table
2.3|[johnnyappleseed@example.com] below query have been working on little while:
select * ws_transaction service_id = 'getusertokenlogin' , service_id '%@%' what supposed give me data table, , make column service_id contain emails, johnnyappleseed email. there wild card out there sql delete useless stuff portrays emails, or have go in different way?
i tried email using percent signs, believe deleting before , after @ not want.
any appreciative
i think can substring email, said have email wrap in square brackets '[ ]', use substring()
declare @a varchar(max) set @a = '2.3|[johnnyappleseed@example.com]' select substring(@a,charindex('[',@a)+1,(charindex(']',@a)-charindex('[',@a))-1);
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