have ever been working on something, found easier way it, completed project, still wanted first way work?
thats i'm @ right now. wanted count number of instances in column recent number , preceding number not equal. decided while loop.
for example,
4 3 2 1 1 1 0 0 0 would return 3, 4 decreases 1 in 3 intervals.
4 4 3 2 1 0 0 would return 0, 4 not decrease in recent interval.
i have written
declare cursor curr select (ytdoverdrafts - previous_ytdoverdrafts) colum (select lag(ytdoverdrafts,1,0) on (order effdate asc) previous_ytdoverdrafts, ytdoverdrafts wh_acctdeposit acctnbr = xxxxxxxxx order effdate desc); counter binary_integer :=0; readcurr curr%rowtype; status integer; begin open curr; fetch curr readcurr; while readcurr.colum > 0 loop counter := counter + 1; dbms_output.put_line(counter); dbms_output.get_line(counter, status); end loop; close curr; end; which runs, not give output should. doing wrong dbms_output statements?
looks single query can this, modified query please check below:
select sum((case when (ytdoverdrafts - previous_ytdoverdrafts) <> 0 1 else 0 end)) non_equal_count (select lag(ytdoverdrafts,1,0) on (order effdate asc) previous_ytdoverdrafts, ytdoverdrafts wh_acctdeposit acctnbr = xxxxxxxxx);
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